WebMar 17, 2024 · Answer: [N2O5] = 0.967 mol/L Fraction which has decomposed = 0.568 Explanation: Step 1: Data given k = 2.8 * 10^−3/s at 60°C The initial concentration of N2O5 is 2.24 mol/L Step 2: Decomposition of N2O5 What kind of order ? The fact that the units of k are reciprocal seconds means it is first order. Rate = k [A] Integrated rate law: WebThe rate constant for the gas-phase decomposition of N2O5, N2O5 2NO2 + 02 has the following temperature dependence: T (K) k (s¯1) 338 4.9 × 10¯ -3 318 5.0 × 10¬4 298 3.5 x 10-5 Make the appropriate graph using these data, and determine the activation energy for this reaction. Question
The reaction 2N2O5 gives 4NO2 + O2 produces O2 at a rate of …
WebN2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs for 3.5 minutes. If the rate constant, k, equals 5.89 … WebFor the decomposition of N 2 O 5 it is given that: 2 N 2 O 5 (g) ⏟ Dinitrogen pentaoxide → 4 NO 2 (g) ⏟ Nitrogen dioxide + O 2 (g) ⏟ Oxygen, Activation energy Ea. N 2 O 5 (g) ⏟ … hay bail wedding seating
The correct mechanism for the decomposition of N2O5 is - Toppr
WebFor the decomposition of N2O5 (e), it is given that N2Osce) →4NO2 (E) + O2 (E) activation energy E. N2O3 (2)→ 2NO2@ +020) activation energy Ea Then (A) E=E: 6) … WebDinitrogen pentoxide between high temperatures of 600 and 1,100 K (327–827 °C), is decomposed in two successive stoichiometric steps: N2O5 → NO2 + NO3 2 NO3 → 2 NO2 + O2 In the shock wave, N2O5 has decomposed stoichiometrically into … WebDec 20, 2024 · The experimental data for decomposition of N 2 O 5 in gas phase at 318K are given below: (i) Plot [N 2 O 5] against t. (ii) Find the half-life period for the reaction. (iii) Draw a graph between log [N 2 O 5] and t. (iv) What is the rate law? (v) Calculate the rate constant. (vi) Calculate the half-life period from k and compare it with (ii). botin charol negro